Python基础篇 tuple
- 2019 年 12 月 26 日
- 笔记
tuple是有序异构容器，用于存储异构元素，列表一旦创建，其内容不可改变。
创建元组核查元素是否位于元组Append , Insert , Modify & delete 元组元素
创建元组
首先定义元组
1In [1]: # 直接创建元组，','分割，使用圆括号 2 ...: tupleObj = ('Riti', 31, 'London', 78.88) 3 ...: tupleObj 4Out[1]: ('Riti', 31, 'London', 78.88)
不使用圆括号
1In [2]: # 直接创建，','分割，不使用圆括号 2 ...: tupleObj = 'Jake', 23, 'paris' , 89.33 3 ...: tupleObj 4Out[2]: ('Jake', 23, 'paris', 89.33)
创建空元组
1In [3]: # 创建空tuple 2 ...: emptyTuple = () 3 ...: emptyTuple 4Out[3]: ()
通过列表创建元组
1In [4]: # 通过 list 创建 tuple 2 ...: listOfNumbers = [12 , 34, 45, 22, 33 ] 3 ...: tupleObj = tuple(listOfNumbers) 4 ...: tupleObj 5Out[4]: (12, 34, 45, 22, 33)
使用 for 循环遍历元素
1In [5]: # 使用 for 循环遍历元素 2 ...: tupleObj = ('Riti', 31, 'London', 78.88) 3 ...: 4 ...: for elem in tupleObj: 5 ...: print(elem) 6 ...: 7Riti 831 9London 1078.88
核查元素是否位于元组
初始化元组
1In [6]: # 初始化tuple 2 ...: tupleObj = (12 , 34, 45, 22, 33 , 67, 34, 56 ) 3 ...: tupleObj 4Out[6]: (12, 34, 45, 22, 33, 67, 34, 56)
使用成员运算符 in / not in 判断元素是否位于 tuple
1In [7]: # 使用成员运算符 in / not in 判断元素是否位于 tuple 2 ...: if 34 in tupleObj: 3 ...: print("Element Found in Tuple") 4 ...: else: 5 ...: print("Element not Found in Tuple") 6 ...: print('*'*30) 7 ...: if 1001 not in tupleObj: 8 ...: print("Yes, element Not In tuple") 9 ...: else: 10 ...: print("Element is in Tuple") 11 ...: 12Element Found in Tuple 13****************************** 14Yes, element Not In tuple
查找元素的索引，语法：tuple.index(x)
1In [8]: # 查找元素的索引，语法：tuple.index(x) 2 ...: try : 3 ...: pos = tupleObj.index(34) 4 ...: print("Element 34 Found at : " , pos) 5 ...: except ValueError as e: 6 ...: print(e) 7 ...: print('*'*30) 8 ...: try : 9 ...: pos = tupleObj.index(24) 10 ...: print("Element 24 Found at : " , pos) 11 ...: except ValueError as e: 12 ...: print(e) 13 ...: 14Element 34 Found at : 1 15****************************** 16tuple.index(x): x not in tuple
核实元素在 tuple 中出现次数，语法：tuple.count(elem)
1In [9]: # 核实元素在 tuple 中出现次数，语法：tuple.count(elem) 2 ...: count = tupleObj.count(34) 3 ...: 4 ...: print("Count of 34 in tuple is : ", count) 5Count of 34 in tuple is : 2
使用 count() 判断元素是否位于 tuple
1In [10]: # 使用 count() 判断元素是否位于 tuple 2 ...: if tupleObj.count(34) > 0 : 3 ...: print("34 Found in Tuple") 4 ...: else: 5 ...: print("34 Not Found in Tuple") 6 ...: 734 Found in Tuple
Append , Insert , Modify & delete 元组元素
元组是不可变的，但是有时候我们需要修改元组，此时只能创建新元组来实现 使用运算符 + 并创建新元组
1In [11]: # 使用运算符 + 并创建新元组 2 ...: tupleObj = (12 , 34, 45, 22, 33 ) 3 ...: print("Original Tuple : ", tupleObj) 4 ...: tupleObj = tupleObj + (19 ,) 5 ...: print("Modified Tuple : ", tupleObj) 6Original Tuple : (12, 34, 45, 22, 33) 7Modified Tuple : (12, 34, 45, 22, 33, 19)
使用切片在指定索引插入元素
1In [12]: # 使用切片在指定索引插入元素 2 ...: tupleObj = (12 , 34, 45, 22, 33 ) 3 ...: print("Original Tuple : ", tupleObj) 4 ...: n = 2 5 ...: # Insert 19 in tuple at index 2 6 ...: tupleObj = tupleObj[ : n ] + (19 ,) + tupleObj[n : ] 7 ...: print("Modified Tuple : ", tupleObj) 8Original Tuple : (12, 34, 45, 22, 33) 9Modified Tuple : (12, 34, 19, 45, 22, 33)
使用切片修改/置换指定索引的元素
1In [13]: # 使用切片修改/置换指定索引的元素 2 ...: tupleObj = (12, 34, 19, 45, 22, 33, 19) 3 ...: print("Original Tuple : ", tupleObj) 4 ...: n = 2 5 ...: # Replace the element at index 2 to 'Test' 6 ...: tupleObj = tupleObj[ : n] + ('test' ,) + tupleObj[n + 1 : ] 7 ...: print("Modified Tuple : ", tupleObj) 8Original Tuple : (12, 34, 19, 45, 22, 33, 19) 9Modified Tuple : (12, 34, 'test', 45, 22, 33, 19)
使用切片删除指定索引的元素
1In [14]: # 使用切片删除指定索引的元素 2 ...: tupleObj =(12, 34, 'test', 45, 22, 33, 19) 3 ...: print("Original Tuple : ", tupleObj) 4 ...: n = 2 5 ...: # Delete the element at index 2 6 ...: tupleObj = tupleObj[ : n ] + tupleObj[n+1 : ] 7 ...: print("Modified Tuple : ", tupleObj) 8Original Tuple : (12, 34, 'test', 45, 22, 33, 19) 9Modified Tuple : (12, 34, 45, 22, 33, 19)
