python脚本 通过rsa priva
- 2020 年 1 月 9 日
- 筆記
说明：蓝色=命令名称
浅绿=命令参数
浅蓝=选项
紫色=目录
系统环境：CentOS 5.5 x86_64
python版本：Python 2.7.3
参考paramiko和pycrypto官方文档写了一个通过rsa private key生成 public key的工具，如下
#!/usr/bin/env python #-*- coding:utf-8 -*- #Author:left_left import struct import base64 import sys import os from optparse import OptionParser from Crypto.PublicKey import RSA def get_bin(n): s = '' n = long(n) while (n != 0) and (n != -1): s = struct.pack('>I', n & 0xffffffffL) + s n = n >> 32 for i in enumerate(s): if (n == 0) and (i[1] != ' 00'): break if (n == -1) and (i[1] != 'xff'): break s = s[i[0]:] if (n == 0) and (ord(s[0]) >= 0x80): s = 'x00' + s if (n == -1) and (ord(s[0]) <0x80): s = 'xff' + s s = struct.pack(">I", len(s)) + s return s def parse(): p = OptionParser() p.set_usage("command [options] privatekey") p.add_option('-p', '--publickey', dest = 'publickey', default = './p.pub') #p.add_option('-v', '--private', dest = 'vf') p.add_option('-t', '--type', dest = 'type', default = 'ssh-rsa') return p def main(): p = parse() options, args = p.parse_args() try: vf = args[0] except IndexError: print "Please use '-h/--help' for help!" sys.exit(1) try: f = open(vf) except IOError, e: print e sys.exit(1) uf = options.publickey if os.path.exists(uf): print "%s is exists!" % uf sys.exit(1) try: k = RSA.importKey(f.read()) except ValueError, e: print e sys.exit(1) s = '' t = options.type l = len(t) s = struct.pack('>I%ss' % l, l, t) e = get_bin(k.e) n = get_bin(k.n) b = base64.b64encode(''.join((s, e, n))) try: of = open(uf, 'w') of.write("%s %sn" % (t, b)) of.close() except IOError, e: print e sys.exit(1) if __name__ == "__main__": main()
