python爬虫之url中的中文问题

在python的爬虫学习中,我们的url经常出现中文的问题, 我们想要访问的url就需要对url进行拼接,变成浏览器可以识别的url 在python中已经有了这样的模块了,这就是urlencode urlencode需要对中文和关键字组成一对字典,然后解析成我们的url

在python2中是 urllib.urlencode(keyword) 在Python中是 urllib.parse.urlencode(keyword)

查看一下代码: python2

import urllib  import  urllib2    #例如我们需要在百度上输入个关键字哈士奇进行查询,但是哈士奇是中文的,我们需要对哈士奇进行编码  keyword = {"wd":"哈士奇"}    head_url = "http://www.baidu.com/s"    headers = {      "User-Agent":"Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36"  }    wd = urllib.urlencode(keyword)  url = head_url +"?"+ wd    req = urllib2.Request(url,headers=headers)    response = urllib2.urlopen(req)  html = response.read()  print(url)  print(html.count('哈士奇'))

结果如下:

在python3中:

# -*- coding: utf-8 -*-  # File  : url中出现的中文问题.py  # Author: HuXianyong  # Date  : 2018-09-13 17:39  from urllib import request  import urllib    #例如我们需要在百度上输入个关键字哈士奇进行查询,但是哈士奇是中文的,我们需要对哈士奇进行编码  keyword = {"wd":"哈士奇"}    head_url = "http://www.baidu.com/s"    headers = {      "User-Agent":"Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36"  }    wd = urllib.parse.urlencode(keyword)  url = head_url +"?"+ wd    req = request.Request(url,headers=headers)    response = request.urlopen(req)  html = response.read()    print(html.decode().count("哈士奇"))    print(url)

结果如下:

如果需要吧转换的字符变成中文 可以用unquota

如下: python2

In [25]: dic = {"say":"你好!"}    In [26]: urllib.urlencode(dic)  Out[26]: 'say=%E4%BD%A0%E5%A5%BD%21'    In [27]: aa  = urllib.urlencode(dic)    In [28]: aa  Out[28]: 'say=%E4%BD%A0%E5%A5%BD%21'    In [29]: bb = urllib.unquote(aa)    In [30]: bb  Out[30]: 'say=xe4xbdxa0xe5xa5xbd!'    In [31]: print(bb)  say=你好!

python3

In [16]: dic = {"say":"你好!"}    In [17]: aa = urllib.parse.urlencode(dic)    In [18]: aa  Out[18]: 'say=%E4%BD%A0%E5%A5%BD%21'    In [19]: bb = urllib.parse.unquote(aa)    In [20]: bb  Out[20]: 'say=你好!'

但是如果我们的是post请求数据需要加在data里面这样就还需要对data做处理,不然会报字符串的错:

TypeError: POST data should be bytes or an iterable of bytes. It cannot be of type str.

这样的解决方法是需要加上个编码 data = urllib.parse.urlencode(formData).encode(encoding="UTF8")

代码如下:

# -*- coding: utf-8 -*-  # File  : Ajax爬取豆瓣电影列表.py  # Author: HuXianyong  # Date  : 2018-09-14 14:35    import urllib  from urllib import request    url = "https://movie.douban.com/j/new_search_subjects?"    headers = {      "User-Agent": "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36"  }    formData = {      "sort": "S",      "range": "0,10",      "tags": "电影,魔幻",      "start": "0",      "genres": "剧情"  }    data = urllib.parse.urlencode(formData).encode(encoding="UTF8")    req = request.Request(url=url,data=data,headers=headers)    response = request.urlopen(req)  move_info = response.read().decode()  print(response.read().decode())